SeriesGroupBy.nlargest()
pandas.core.groupby.SeriesGroupBy.nlargest
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SeriesGroupBy.nlargest(*args, **kwargs)
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Return the largest
n
elements.Parameters: n : int
Return this many descending sorted values
keep : {‘first’, ‘last’, False}, default ‘first’
Where there are duplicate values: -
first
: take the first occurrence. -last
: take the last occurrence.take_last : deprecated
Returns: top_n : Ser